select customer_id,count(order_id) as total_orders, sum(amount) as total_spend from orders group by customer_id having count(order_id) >=3 select name, price, case ...
This page contains solutions for all HackerRank SQL challenges which were passed successfully. There can be multiple ways of approaching solution to any problem. Please find the provided solutions for ...
Some results have been hidden because they may be inaccessible to you
Show inaccessible results